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152 lines
4.1 KiB
152 lines
4.1 KiB
8 years ago
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#include "map/Octree.h"
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Octree::Octree() {
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// initialize the first stack block
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for (int i = 0; i < 0x8000; i++) {
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blob[i] = 0;
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}
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}
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uint64_t Octree::copy_to_stack(std::vector<uint64_t> children) {
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// Check for the 15 bit boundry
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if (stack_pos - children.size() > stack_pos) {
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global_pos = stack_pos;
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stack_pos = 0x8000;
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}
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else {
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stack_pos -= children.size();
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}
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// Check for the far bit
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memcpy(&blob[stack_pos + global_pos], children.data(), children.size() * sizeof(uint64_t));
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// Return the bitmask encoding the index of that value
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// If we tripped the far bit, allocate a far index to the stack and place
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// it at the bottom of the child_descriptor node level array
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// And then shift the far bit to 1
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// If not, shift the index to its correct place
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return stack_pos;
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}
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bool Octree::get_voxel(sf::Vector3i position) {
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// Struct that holds the state necessary to continue the traversal from the found voxel
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oct_state state;
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// push the root node to the parent stack
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uint64_t head = blob[root_index];
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state.parent_stack[state.parent_stack_position] = head;
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// Set our initial dimension and the position at the corner of the oct to keep track of our position
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int dimension = OCT_DIM;
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sf::Vector3i quad_position(0, 0, 0);
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// While we are not at the required resolution
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// Traverse down by setting the valid/leaf mask to the subvoxel
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// Check to see if it is valid
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// Yes?
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// Check to see if it is a leaf
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// No? Break
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// Yes? Scale down to the next hierarchy, push the parent to the stack
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//
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// No?
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// Break
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while (dimension > 1) {
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// So we can be a little bit tricky here and increment our
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// array index that holds our masks as we build the idx.
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// Adding 1 for X, 2 for Y, and 4 for Z
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int mask_index = 0;
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// Do the logic steps to find which sub oct we step down into
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if (position.x >= (dimension / 2) + quad_position.x) {
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// Set our voxel position to the (0,0) of the correct oct
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quad_position.x += (dimension / 2);
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// increment the mask index and mentioned above
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mask_index += 1;
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// Set the idx to represent the move
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state.idx_stack[state.scale] |= idx_set_x_mask;
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}
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if (position.y >= (dimension / 2) + quad_position.y) {
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quad_position.y |= (dimension / 2);
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mask_index += 2;
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state.idx_stack[state.scale] ^= idx_set_y_mask;
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}
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if (position.z >= (dimension / 2) + quad_position.z) {
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quad_position.z += (dimension / 2);
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mask_index += 4;
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state.idx_stack[state.scale] |= idx_set_z_mask;
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}
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// Check to see if we are on a valid oct
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if ((head >> 16) & mask_8[mask_index]) {
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// Check to see if it is a leaf
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if ((head >> 24) & mask_8[mask_index]) {
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// If it is, then we cannot traverse further as CP's won't have been generated
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return true;
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}
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// If all went well and we found a valid non-leaf oct then we will traverse further down the hierarchy
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state.scale++;
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dimension /= 2;
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// Count the number of valid octs that come before and add it to the index to get the position
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// Negate it by one as it counts itself
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int count = count_bits((uint8_t)(head >> 16) & count_mask_8[mask_index]) - 1;
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// access the element at which head points to and then add the specified number of indices
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// to get to the correct child descriptor
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head = blob[(head & child_pointer_mask) + count];
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// Increment the parent stack position and put the new oct node as the parent
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state.parent_stack_position++;
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state.parent_stack[state.parent_stack_position] = head;
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}
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else {
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// If the oct was not valid, then no CP's exists any further
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// This implicitly says that if it's non-valid then it must be a leaf!!
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// It appears that the traversal is now working but I need
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// to focus on how to now take care of the end condition.
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// Currently it adds the last parent on the second to lowest
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// oct CP. Not sure if thats correct
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return false;
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}
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}
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return true;
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}
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void Octree::print_block(int block_pos) {
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std::stringstream sss;
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for (int i = block_pos; i < (int)pow(2, 15); i++) {
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PrettyPrintUINT64(blob[i], &sss);
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sss << "\n";
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}
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DumpLog(&sss, "raw_data.txt");
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}
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